Pre-Equilibria Conditions in Reaction Mechanisms?

L

LookingSharp

New member
5Br-(aq) + BrO3-(aq) + 6H+(aq) --> 3Br2(l) + 3H2O(l)

The above reaction is expected to obey the mechanism:
BrO3-(aq) + H+(aq) = HBrO3(aq) Fast equilibrium

HBrO3(aq) + H+(aq) = H2BrO3+(aq) Fast equilibrium

H2BrO3+(aq) + Br-(aq) --> (Br-BrO2)(aq) + H2O(l) Slow

(Br-BrO2)(aq) + 4H+(aq) + 4Br-(aq) --> products Fast



Choose, from the list below, correct expressions for the overall rate law which are completely consistent with the above mechanism.

k[Br-][H+]2[BrO3-] = -d[Br-]/dt

-d[H+]/dt = k[BrO3-][Br-][H+]2

-d[BrO3-]/dt = k[Br-]2[BrO3-][H+]

-d[Br-]/dt = k[Br-][H+]2[BrO3-]

d[Br-BrO2]/dt = k[Br-][BrO3-][H+]2

-d[Br-]/dt = k[Br-][BrO3-][H+]
 
Back
Top