N nyswthun New member Dec 8, 2010 #1 Interval [0, 2pi) 2 sin^2x-cosx-1=0 What is the solution set??? When i factored i got: -(2 sinx-1)(sinx+1)=0 sin x= -1/2 and -1 so isn't it solution set is: pi/3, 5pi/3, and 3pi/2??? Please help. thnxs
Interval [0, 2pi) 2 sin^2x-cosx-1=0 What is the solution set??? When i factored i got: -(2 sinx-1)(sinx+1)=0 sin x= -1/2 and -1 so isn't it solution set is: pi/3, 5pi/3, and 3pi/2??? Please help. thnxs
