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Pre Calc question please help asap?
- Thread starter Jordan
- Start date
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
youngandinsane
New member
horizontal asymptote is anywhere where the slope=0
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there
slope=rise over run so rise (or the y value) has to be equal to 0
0=(6x+24)(3x-1)/(8-x)(2x+2)
and you just do all the algebra from there