If your vertex is 2, -5 that is your h,k. The point of 4,7 is your x,y. From there you just plug in and solve for a. Once you find a, you rewrite the equation including the a, h, and k so the only variables left are y and x. In that way, it is still an equation because you have 2 variables, and the equation can be reused with any new points that it passes through.
Pre-Calc question! help!?
- Thread starter Jennifer
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find an equation for the parabola having vertex (2, -5) and passing through the point (4,7). Express your answer in the vertex form for a quadratic function.
i know the vertex form is y=a(x-h)^2 + k and (h,k) is the vertex. but i dont know where to go from there. please help! thanks
i know the vertex form is y=a(x-h)^2 + k and (h,k) is the vertex. but i dont know where to go from there. please help! thanks