Pre-Calc help please trying to study for my final?

jloe1705

New member
a) enter the equation into a graphing calculator in this case V(t) would be the "y =" part and t would be X

b) put 2 in for t, so you have V(2) = 14000*(3/4)^2

c) To see where the car depreciates most rapidly look at the graph of the equation. Where the slope is the steepest is where the car depreciates most rapidly. It will be realistic if the slope is steepest at the beginning of the graph (for lower values of t) and the steepness will decrease over time and almost flatten out.
 
Depretiation After t years, the value V of a car that origanally cost $14,000 is given by V(t)= 14,000(3/4)^t

a) Use a graphing utility to graph the function
b) Find the value of the car 2 years after it was purchase.
c)According to the model, when does the car depreciate most rapidly? Is this realistic? Explain
 
a) enter the equation into a graphing calculator in this case V(t) would be the "y =" part and t would be X

b) put 2 in for t, so you have V(2) = 14000*(3/4)^2

c) To see where the car depreciates most rapidly look at the graph of the equation. Where the slope is the steepest is where the car depreciates most rapidly. It will be realistic if the slope is steepest at the beginning of the graph (for lower values of t) and the steepness will decrease over time and almost flatten out.
 
Back
Top