plz i need help in chemistry..?

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1)0.35g of sodium hydroxide (NaOH) pellets are dissolved in water to make 8.0 L of solution. What is the pH of this solution?
2)0.65g of hydrogen chloride (HCL) is dissolved in water to make 5.0L of solution. What is the pH of the resulting hydrochloric acid solution?
plz could you explain how to find, thanks!!
 
1)
moles NaOH = 0.35 g / 40 g/mol=0.00875
Molarity NaOH = 0.00875/ 8.0 L=0.0011
pOH = - log 0.0011 = 3.0
pH = 14 - 3.0 = 11


2)
moles HCl = 0.65 g / 36.461 g/mol=0.0178
molarity HCl = 0.0178/ 5.0 L=0.0036 M
pH = - log 0.0036=2.4
 
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