Please help with physics?

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xMidnightDarknessx

New member
A sports car is advertised to be able to stop in a distance of 60 m from a speed of 100 km/h.
(a) What is its acceleration in m/s2?
(b) How many g's is this (g = 9.80 m/s2)?
 
to calculate acceleration we require certain physical quantities one of the most important one is velocity.......... to find velocity we need displacement or the direction of the distance ..........so displacement is missing in your problem...........so check your question.
 
Displacement S = 60 m
Initial velocity vi = 100 km/h = 100 * 1000/3600 m/s = 250/9 m/s
Final velocity vf = 0

a) Let acceleration = a
vf^2 = vi^2 + 2aS
0 = (250/9)^2 + 2(a)(60)
0 = 771.6 + 120 a
a = -771.6/120 = -6.43 m/s^2
Magnitude of acceleration = 6.43 m/s^2

b) a/g = 6.43/9.80 = 0.66
Ans: 0.66 g's
 
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