I don't know what "I=P/A" is--but for this problem you'll have to use some algebra, and you'll have to know two facts:
1. Speed of sound through 0C air;
2. Speed of sound through 20C air.
I don't know what those speeds are (you'll have to look them up or use some formula that's in your book); but for now let's use these variables:
V0 = speed of sound through 0C air;
V20 = speed of sound through 20C air;
D0 = thickness of 0C layer;
D20 = thickness of 20C layer.
Now the time it takes for (anything) to go distance "D" when traveling at speed "V" is given by this formula:
Time = D/V
So, the time it takes for the sound to go through both layers is:
Total time = (time through 0C layer) + (time through 20C layer)
Total time = (D0/V0) + (D20/V20)
The problem tells you that the total time is 4.5 sec., so:
4.5 sec. = (D0/V0) + (D20/V20)
Also, the problem tells you that the total distance is 1500 meters. This is the sum of the thicknesses of the two layers, so:
1500 meters = D0 + D20
You now have two equations in two unknowns (D0 and D20). Use algebra to solve them simultaneously.
1. Speed of sound through 0C air;
2. Speed of sound through 20C air.
I don't know what those speeds are (you'll have to look them up or use some formula that's in your book); but for now let's use these variables:
V0 = speed of sound through 0C air;
V20 = speed of sound through 20C air;
D0 = thickness of 0C layer;
D20 = thickness of 20C layer.
Now the time it takes for (anything) to go distance "D" when traveling at speed "V" is given by this formula:
Time = D/V
So, the time it takes for the sound to go through both layers is:
Total time = (time through 0C layer) + (time through 20C layer)
Total time = (D0/V0) + (D20/V20)
The problem tells you that the total time is 4.5 sec., so:
4.5 sec. = (D0/V0) + (D20/V20)
Also, the problem tells you that the total distance is 1500 meters. This is the sum of the thicknesses of the two layers, so:
1500 meters = D0 + D20
You now have two equations in two unknowns (D0 and D20). Use algebra to solve them simultaneously.