sereneecho
New member
A&Bsolved I need assistance with C&D? A point charge of +7.0 nC is fixed at position (0.0 , 5.0) m. A second point charge of -2.0 nC is fixed at position (-3.0 , 0.0) m. (a) Calculate the electric field (magnitude and direction) at position (0.0, 0.0) m. (b) Calculate the electric potential at position (0.0, 0.0) m. (c) Using your result from part a, calculate the net force (magnitude and direction) on a +1.5 nC charge placed at (0.0, 0.0) m. (d) Using your result from part b, calculate the electric potential energy due to the interaction between (not among) a +1.5 nC charge placed at (0.0, 0.0) m and the pair of point charges.
I think I have part A&B correct (but I'm stuck on the rest):
a)
magnitude = 3.22x109
direction = 52 degrees from x axis
b)
Distance of q1 from origin; r1 = sqrt[0.0m^2 + 5.0m^2] = 5.0m
Distance from q2 from origin; r2 = sqrt[-3.0m^2 + 0.0m^2] = 3.0m
Electric potential at the origin V = (kq1/r1)+(kq2/r2) = (8.99e^9N.m^2/C^2)[(4.0e^-6C/5.0m)+(-2.0e^-6C/3.0m)] = 1198.67
I think I have part A&B correct (but I'm stuck on the rest):
a)
magnitude = 3.22x109
direction = 52 degrees from x axis
b)
Distance of q1 from origin; r1 = sqrt[0.0m^2 + 5.0m^2] = 5.0m
Distance from q2 from origin; r2 = sqrt[-3.0m^2 + 0.0m^2] = 3.0m
Electric potential at the origin V = (kq1/r1)+(kq2/r2) = (8.99e^9N.m^2/C^2)[(4.0e^-6C/5.0m)+(-2.0e^-6C/3.0m)] = 1198.67