A steel ball rolls with constant velocity across a tabletop 0.950 m high. It rolls off and hits the ground +0.352 m horizontally from the edge of the table. How fast was the ball rolling? (ans is :0.800 m/s)
the answer is 0.800 m/s but i dont how the answer was found
Let the ball take t sec to fall the vertical height of 0.950m,
By s = ut + 1/2gt^2
=>0.950 = 0 + 1/2 x 9.8 x t^2
=>t = sqrt[0.19] = 0.44 sec
For the horizontal distance covered in t sec,By
s = [Ux] x t
=>0.352 = [Ux] x 0.44
=>Ux = 0.80 m/s
