Physics- Spring, mass on an incline?

A

Ally

New member
A spring is mounted at an angle of theta = 35degrees on a frictionless incline as illustrated in the figure below. The spring is compressed to 15 cm where it is allowed to propel a mass of 4.6 kg up the incline.
(a) If the spring constant is 575 N/m, how fast is the mass moving when leaves the spring?
(b) To what maximum distance from the starting point will the mass rise up the incline?
 
a)
Spring PE = Mass KE
1/2 kx^2 = 1/2 mv^2
575 * 0.15 *0.15 = 4.6 v^2
v= 1.68 m/s
-----------------------------------
b) Spring PE = Mass PE
1/2 kx^2 = mgh
h= (1/2 * 575 * 0.15 * 0.15) / (9.8* 4.6)
h= 0.1435 m
now s= h/ sin 35 = 0.25 m
= 25 cm
 
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