Physics regarding distance/displacement problem.?

W

Waleed

New member
A golfer takes putts to get the ball into the hole. the first putt displaces the ball 3.66m north. the second 1.83m southeast and the third 0.91m southwest. What are
(a) the magnitude?
(b) The direction of the displacement needed to get the ball into the hole on the first putt?

Please answer with appropriate answers ... thank you.
 
the answer would be 0.92 North- East.

A easy way to do it is :

Displacement = 3.66N+1.83S+1.83E+0.91S+0.91W
= 3.66N+2.74S+1.83E+0.91W
Now, Subtract east with west and North With South Coz u r supposed to subtract opposite direction.

Thus,
=0.92N+0.92E
=0.92N/E.
You can also do it with resolution of vector method by drawing appropriate diagram.
 
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