A force F, with a magnitude of 21.3 N, acts on an object with a mass of m = 1.12 kg parallel to the plane of the incline.
The angle of the incline is θ = 41.9°. The object is observed to move at a constant velocity of 2.94 m/s up on the incline. Calculate the magnitude of the frictional force acting on the object.
So the answer is 14 N.. But i am not sure how they got it. Could someone explain please? thanks!
The angle of the incline is θ = 41.9°. The object is observed to move at a constant velocity of 2.94 m/s up on the incline. Calculate the magnitude of the frictional force acting on the object.
So the answer is 14 N.. But i am not sure how they got it. Could someone explain please? thanks!