R
rugbuddy
Guest
A physics student playing with an air hockey table (a frictionless surface) finds that if she gives the puck a velocity of 3.84 m/s along the length ( 1.66m ) of the table at one end, by the time it has reached the other end the puck has drifted a distance 2.49m to the right but still has a velocity component along the length of 3.84 . She concludes correctly that the table is not level and correctly calculates its inclination from the above information.
What is the angle of inclination?
I've seen lots of questions like this on here before, and I follow the steps, but still get the wrong answer.
t = 1.66 / 3.84 seconds
During this time, it moves 2.56 cm in the transverse direction.
2.56 = 1/2 at^2
a = 26.65 cm/s^2
a= 0.2665 m/s^2
.2665=9.81*sin(theta)
sin(theta)=.027165
theta=.027168????
I am totally confused...
What is the angle of inclination?
I've seen lots of questions like this on here before, and I follow the steps, but still get the wrong answer.
t = 1.66 / 3.84 seconds
During this time, it moves 2.56 cm in the transverse direction.
2.56 = 1/2 at^2
a = 26.65 cm/s^2
a= 0.2665 m/s^2
.2665=9.81*sin(theta)
sin(theta)=.027165
theta=.027168????
I am totally confused...