O oden New member Oct 22, 2009 #1 A man walks up a hill at a speed of 8.0m/s. When he reaches the top, he walks back down at thesame distance at a speed of 12.0m/s. What is the average speed for the trip?
A man walks up a hill at a speed of 8.0m/s. When he reaches the top, he walks back down at thesame distance at a speed of 12.0m/s. What is the average speed for the trip?
R Robrecht Guest Oct 22, 2009 #3 Combine given data: t = d/8 + d/12 = 20d/96 12d/96 + 8d/96 = 20d/96 Distance = 2d (meters) V average = D/t = 2d/(20d/96) = 9.6 m/s Average speed = total distance/total time
Combine given data: t = d/8 + d/12 = 20d/96 12d/96 + 8d/96 = 20d/96 Distance = 2d (meters) V average = D/t = 2d/(20d/96) = 9.6 m/s Average speed = total distance/total time
