Three children 50kg, 70kg, & 100kg wish to balance a see-saw. If the 100kg child sits 1.5m from the pivot on the left and the 70kg child sits 1.5m from the pivot on the right end, where must the 50kg child sit to achieve balance.
so far I have: Fnet=ma
F1=(50kg)(9.8 m/s^2)=490N
F2=(70kg)(9.8 m/s^2)=686N
F3=(100kg)(9.8 m/s^2)=980N
now what?
so far I have: Fnet=ma
F1=(50kg)(9.8 m/s^2)=490N
F2=(70kg)(9.8 m/s^2)=686N
F3=(100kg)(9.8 m/s^2)=980N
now what?