J
Jonathon M
Guest
Ok I want to post the name of the file I uploaded to MYsql Database uploads in the 'name' field
<?php
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
}
?>
<?php
$dnname = $_POST[name];
$con = mysql_connect("localhost","root","majick");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("warezzf", $con);
$result=mysql_query("INSERT INTO uploads (name) VALUES ('$dnname')");
mysql_close($con);
?>
This code echos the correct information but puts it in my DBV as blank, Thanks to anyone who answers these as they are annoying :>
<?php
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
}
?>
<?php
$dnname = $_POST[name];
$con = mysql_connect("localhost","root","majick");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("warezzf", $con);
$result=mysql_query("INSERT INTO uploads (name) VALUES ('$dnname')");
mysql_close($con);
?>
This code echos the correct information but puts it in my DBV as blank, Thanks to anyone who answers these as they are annoying :>