Parking violation notice...

were you educated in the projects? It comes out to an even 25 plain and simple.
Let me check again:

First I'll take the 7 out of the sigma. Now the sigma is running from n=1 to infinity with n-1 as the exponent, which is like a sigma running from n=0 to infinity with an exponent of n. For a sigma running to infinity from n=0, the formula is 1/(1-q), for |q| < 1. Therefore:

Sigma((0.8)^n) = 1/(1-0.8) = 1/0.2 = 5
==> 7*Sigma((0.8)^n) = 7*5 = 35

13.574 + (2*(e^(2*pi))) =~ 13.574 + 2*2.71^(6.28) = 1084.55731

==> 13.574 + (2*(e^(2*pi))) - 7*Sigma((0.8)^n) = 1084.55731 - 35 = 1049.55731 25

Well, enough geekness for one day? :lol:
 
Back
Top