J Jaholbrook983 New member Jan 9, 2010 #1 An object is thrown upwards with a speed of 13m/s. How long does it take to reach a height of 4.0m above the projection point while descending?
An object is thrown upwards with a speed of 13m/s. How long does it take to reach a height of 4.0m above the projection point while descending?
C climberguy12 New member Jan 9, 2010 #2 x=1/2at^2+vot 4=1/2(-9.8)t^2+13t quadratic formula... a=-4.9,b=13,c=-4 t=.355,2.298 the first one would be on the way, up so it is 2.298 seconds make it a good day
x=1/2at^2+vot 4=1/2(-9.8)t^2+13t quadratic formula... a=-4.9,b=13,c=-4 t=.355,2.298 the first one would be on the way, up so it is 2.298 seconds make it a good day
C climberguy12 New member Jan 9, 2010 #3 x=1/2at^2+vot 4=1/2(-9.8)t^2+13t quadratic formula... a=-4.9,b=13,c=-4 t=.355,2.298 the first one would be on the way, up so it is 2.298 seconds make it a good day
x=1/2at^2+vot 4=1/2(-9.8)t^2+13t quadratic formula... a=-4.9,b=13,c=-4 t=.355,2.298 the first one would be on the way, up so it is 2.298 seconds make it a good day