A 75.0kg student is standing on a bathroom scale on an elevator that is accelerating downwards at 1.00m/s^2. What is the students apparent weight in newtons?
g = 9.81 m/s²
a = elevator's acceleration = 1.00 m/s²
effective downward acceleration ge = 9.81 - 1.00 = 8.81 m/s³
m = mass of student = 75.0 kg
Apparent weight of stufent in elevatior = m(ge) = (75.0)(8.81) = 661 N ANS
