Moving the graph of y=e^x?

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Steve

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The problem is as follows:

Consider the graph of y=e^x
(a) Find the equation of the graph that results from reflecting about the line y = 6.

(b) Find the equation of the graph that results from reflecting about the line x = 5.

I thought that this was pretty basic with (a) being y=(-e^x)+6 and (b) being y=e^(-x-5) but the I keep getting the wrong answer according to the assignment.

any help would be appreciated.

Thanks
 
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