Starting from rest at t=0sec, a tire on a mountain bike has a constant angular acceleration. When t= 5 sec, the angular velocity of the wheel is 6.6 rad/sec. The angular acceleration continues until t= 17 sec, after which the angular velocity remains constant. The tire has a radius of 22cm.
e) What would be the linear displacement of the tire's axle as it moves forward from t=0sec to t=17 sec?
from previous questions, I got the following correct answers:
angular acceleration at t= 17 sec? --> 1.32 rad / s /s
angular velocity at t= 17 sec? --> 22.44 rad /s
total angular displacement of the tire from t=0sec to t=17 sec? --> 190.74 rad
e) What would be the linear displacement of the tire's axle as it moves forward from t=0sec to t=17 sec?
from previous questions, I got the following correct answers:
angular acceleration at t= 17 sec? --> 1.32 rad / s /s
angular velocity at t= 17 sec? --> 22.44 rad /s
total angular displacement of the tire from t=0sec to t=17 sec? --> 190.74 rad