I'm embarrassed to say that I don't know the answer but here is the question:
2.)(4 pts)Using the 36-bit address of problem 1, and assuming a 64-bit word, how many words can the computer address? Remember, it is a byte addressable machine.
If it helps the previous question was:
1.)(4 pts)In decimal (exactly), if a computer has a 36-bit address for every byte in memory, how many memory locations can this computer address?
and i'm ~99% sure the answer is 2^36 = 68,719,476,736
10 points for the most informative (correct) answer.
-Much thanks
2.)(4 pts)Using the 36-bit address of problem 1, and assuming a 64-bit word, how many words can the computer address? Remember, it is a byte addressable machine.
If it helps the previous question was:
1.)(4 pts)In decimal (exactly), if a computer has a 36-bit address for every byte in memory, how many memory locations can this computer address?
and i'm ~99% sure the answer is 2^36 = 68,719,476,736
10 points for the most informative (correct) answer.
-Much thanks