C
Chris
Guest
A large rock is thrown up at an initial speed of 10m/s from a height of 25 m above the ground. Its height above the ground h in meters as a function of time t in seconds is given by the function:
h(t)= -4.9^2+10t+25
The velocity of the rock v in meters per second as a function of the time t given by the function:
v(t)= -9.8t+10
Find:
a) Based on the physical interpretation of the functions, what should be the domain of the function?
b) Find the maximum height of the rock and the time when it reaches maximum height.
c) Find the time when the rock hits the ground.
d) Graph the height as a function of time.
e) Graph the velocity as a function of time. A positive velocity means the rock is going up and a negative velocity means the rock is going down.
h(t)= -4.9^2+10t+25
The velocity of the rock v in meters per second as a function of the time t given by the function:
v(t)= -9.8t+10
Find:
a) Based on the physical interpretation of the functions, what should be the domain of the function?
b) Find the maximum height of the rock and the time when it reaches maximum height.
c) Find the time when the rock hits the ground.
d) Graph the height as a function of time.
e) Graph the velocity as a function of time. A positive velocity means the rock is going up and a negative velocity means the rock is going down.