C
Curt Monash
Guest
Differentiate both sides of the first equation with respect to x.
The RHS of course differentiates to 0. The LHS has terms in x, y, and y'. You know what the first two are when x = 2, so substitute those values in and you'll have a simple equation for y'(2).
The RHS of course differentiates to 0. The LHS has terms in x, y, and y'. You know what the first two are when x = 2, so substitute those values in and you'll have a simple equation for y'(2).