Inverse of an image (i.e. pre image) - please help?

pravaluvian

New member
In class we showed that for f: R -> R where f(x) = x^2, f^-1 ((-1,2)) = (-sqrt(2), sqrt(2)).

Similarly, what is f^-1 ((0,1)) for

f: R->R defined by f(x) = (x+1) / (x^2 + 1)
 
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