Blocks2hell
New member
There is a water tank which is 2m high, it is full and contains 20,000L of water. There is an output in the side of the tank which leads to a tap 20m vertically below the bottom output of the water tank. What is the potential energy of the water relative to the output.
My class has came up with three different answers:
1)You measure the height from the bottom of the water tank and so the potential energy is
PE = 20000*9.8*20 = 3920000J
2)You measure the height from the top of the water tank so the potential energy is
PE = 20000*9.8*22 = 4312000J
3)You measure the height from the middle of the water tank so the potential energy is
PE = 20000*9.8*21 = 4116000J
I think the answer is 1. I think you should disregard everything but the water and therefore have the water suspended 20m high and just calculate the PE.
What do you think, justify your answer?
My class has came up with three different answers:
1)You measure the height from the bottom of the water tank and so the potential energy is
PE = 20000*9.8*20 = 3920000J
2)You measure the height from the top of the water tank so the potential energy is
PE = 20000*9.8*22 = 4312000J
3)You measure the height from the middle of the water tank so the potential energy is
PE = 20000*9.8*21 = 4116000J
I think the answer is 1. I think you should disregard everything but the water and therefore have the water suspended 20m high and just calculate the PE.
What do you think, justify your answer?