If y = arctan[root(7x^2-1)], then dy/dx = ?

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futuredoc_christie

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I thought d/dx(arctanx) = 1/(1+x^2), so when you square a square root, the inside comes out, so it would be 1/(1+7x^2-1) = 1/7x^2, but it's telling me that's the wrong answer... so what am I doing wrong?
 
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