I need help with chemistry?

S

Stimpy

New member
Heat lost by nickel = Heat gained by water

heat gained or lost q = m c ∆T

-275g x 0.444J/gC x (Tf - 100) = 100g x 4.18J/gC x (Tf - 22)

just solve for Tf (temperature final)

notice I put a negative sign in front of heat lost by nickel since it is loosing heat.

Your final answer should be very close to 40 degrees Celsius
 
275 g sample of nickel at 100 degrees Celsius is placed in 100 g of water at 22 degrees Celsius. What is final temp. of water? Assume no heat is lost or gained, specific heat of nickel =.444J/g*C) specific heat of water is 4.18J/g*C)
 
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