How do you find intersection of a sphere when the center and radius is given?

  • Thread starter Thread starter Amita P
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Amita P

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Given: Center (4,4,3) Radius : 5
Find the equation of the sphere
so I got: (x-4)^2 + (y-4)^2 + (z-3)^2 = 25

I need help finding: the intersection of this sphere with the xz plane, y=0
 
If y = 0, y - 4 = -4, squared is 16 so add -16 to both sides
(x - 4)^4 + (z - 3)^2 = 9

So it's a circle with radius 3 centered at (4, 0, 3) which is (4,3) on the (x,z) plane
 
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