itsSCIENCE
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At 25 degrees Celsius, the standard enthalpy of formation of HF(aq) is -320.0 kJ/mol. Of OH-(aq), it is -229.5 kJ/mol. Of F-(aq) it is -329.6 kJ/mol, and of H2O(l) it is -286.0 kJ/mol.
Calculate the standard enthalpy of neutralization of HF(aq):
HF(aq) + OH(aq) --> F-(aq) + H2O(l)
Calculate the standard enthalpy of neutralization of HF(aq):
HF(aq) + OH(aq) --> F-(aq) + H2O(l)