onigiri san
New member
Given that there are 6.02 x 10^23 particles in one mole of any substance, calculate the mass of water containing 3.3 x 10^23 atoms.
the answer to this according to the answers is 3.3g
i think this is how u do it
so
no. moles = 3.3 x 10^23 / 6.02 x 10^23
=0.5481...
then m = 0.5481 x (1.008 x 2 +16)
= 9.875....
then u gtta divided m by 3 which = 3.291...g
this is wat my teacher said, but now im confused as to y you have to divide by 3, please explain, otherwise if my method is wrong how do u do it, and can u explain it properly. thanks
oh, he said that u divide by 3 cos H2O contains 3 atoms... but i still don't understand, could anyone elaborate?
the answer to this according to the answers is 3.3g
i think this is how u do it
so
no. moles = 3.3 x 10^23 / 6.02 x 10^23
=0.5481...
then m = 0.5481 x (1.008 x 2 +16)
= 9.875....
then u gtta divided m by 3 which = 3.291...g
this is wat my teacher said, but now im confused as to y you have to divide by 3, please explain, otherwise if my method is wrong how do u do it, and can u explain it properly. thanks
oh, he said that u divide by 3 cos H2O contains 3 atoms... but i still don't understand, could anyone elaborate?