help prove x[n]<->xd(w)....sampling rate?

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Prove:

x[n] <-> xd(w)

...........^^ x has bar on top and bottom. and d is subscript

Also,

x[n] <--> e^(jwk) xd(w)
.........................^^ x has bar on top and bottom. and d is subscript


Can Use: xd(w) = E(from inf on top and n=-inf on bottom) x[n]e^-(jwn)
...............^^ x has bar on top and bottom. and d is subscript
 
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