K
k0nstantine
Guest
The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m in a direction 23.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of vector vector C is 18.0° north of west. The hiker ends up back where she started, so the resultant displacement is zero, or A+ B + C = 0. Find the magnitudes of vector B and vector C.
So I got that my equations for the x components should be:
(1550xcos23)+(Bsin41)-(Ccos41)=0
And that my y components should be:
(1550xsin23)-(Bcos41)+Csin18
and I know I'm supposed to add them together somehow but I either have messed up my calculations or I'm adding them wrong. Could someone please help me out?? (Thank you ahead of time!)
So I got that my equations for the x components should be:
(1550xcos23)+(Bsin41)-(Ccos41)=0
And that my y components should be:
(1550xsin23)-(Bcos41)+Csin18
and I know I'm supposed to add them together somehow but I either have messed up my calculations or I'm adding them wrong. Could someone please help me out?? (Thank you ahead of time!)