The boiling point of pure benzene, C6H6, at 760 torr is 80.1*C. What would be the vapor pressure of benzene over a solution containing 1.00 mol of a nonvolatile hydrocarbon and 12.0 mol of benzene at 80.1*C?
How would I go about solving this problem? I am completely lost.
Also, Which of the following has the least effect on the solubility of a solid in a liquid solvent?
a. temperature
b. nature of the solvent
c. nature of the solute
d. pressure (I think it's pressure, but I'm not entirely sure.)
Where did the 13 come from?
Did it come from the C6H6, which has 2 moles, and then the 1 mole of nonvolatile hydrocarbon?
Sorry, I meant 12 moles
How would I go about solving this problem? I am completely lost.
Also, Which of the following has the least effect on the solubility of a solid in a liquid solvent?
a. temperature
b. nature of the solvent
c. nature of the solute
d. pressure (I think it's pressure, but I'm not entirely sure.)
Where did the 13 come from?
Did it come from the C6H6, which has 2 moles, and then the 1 mole of nonvolatile hydrocarbon?
Sorry, I meant 12 moles