Fruit Flies phenotypes, AP Biology 2003 question 1?

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Fruit Flies phenotypes, AP Biology 2003 question 1?
This is from the AP Biology 2003

1. In fruit flies, the phenotype of eye color is determined by a certain locus. E indicates the dominant allele and e indicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eye fruit fly produced the following offspring.

F1

Wild type Male =0
Wild type Female= 45
White-eyed Male= 55
White-eyed Female= 0
Brown eyed Female= 1

The wild type and white eyed individuals from the F1 generations were crossed to produce the following offspring

F2


Wild type Male =23
Wild type Female=31
White-eyed Male= 22
White-eyed Female= 24
Brown eyed Female= 0


(a) Determine the genotypes of the original parents and explain your reasoning. You may use Punnet squares to enhance your description, but the results from the Punnett squares must be discussed in your answer.

(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Show all your work and explain the importance of your final answer.

(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is and discuss two types of mutations that might have produced the brown-eyed female in the F1 generation.



help please!
 
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