Finding moment of inertia.. A 0.90 m diameter wagon wheel consists of a thin rim having

[akm69]

I(total) = I(spoke) + I(rim)
=>I(t) = 6 x 1/2 x 1.60 x (0.90/2)^2 + 1/2 x 10 x (0.90)^2 = 5.022 kg-m^2

 

[akm69]

I(total) = I(spoke) + I(rim)
=>I(t) = 6 x 1/2 x 1.60 x (0.90/2)^2 + 1/2 x 10 x (0.90)^2 = 5.022 kg-m^2

 

[Ryan]

a mass of 10.00 kg ...? A 0.90 m diameter wagon wheel consists of a thin rim having a mass of 10.00 kg and six spokes each having a mass of 1.60 kg. Determine the moment of inertia of the wagon wheel for rotation about its axis.

I thought I should have gotten this by splitting it up into two parts, but I'm doing something wrong. Should be fairly simple. Thanks for any help!