niceguylamps
New member
Find the equation of the normal to the curve; 2x^3 - x(^2)y + y^3 = 1
at the point (2, -3)
So I used implicit differentiation to get the gradient of the tangent.
2x^3 - x(^2)y + y^3 = 1
dy/dx = (2xy - 6x^2) / (3y^2 - x^2) at (2,-3)
= -36 / 23 = Gradient = m
Now I use y - y1 = m(x -x1) to get the equation of the tangent.
I'm having trouble here, arranging the equation.
What am I doing wrong?
y - y1 = m(x -x1)
y + 3 = -36/23 (x - 2)
y + 3 = (-36/23)x + 72/23
Not sure how to arrange that.
The gradient and equation of the normal will be easier if I knew how to arrange this.
Thanks.
at the point (2, -3)
So I used implicit differentiation to get the gradient of the tangent.
2x^3 - x(^2)y + y^3 = 1
dy/dx = (2xy - 6x^2) / (3y^2 - x^2) at (2,-3)
= -36 / 23 = Gradient = m
Now I use y - y1 = m(x -x1) to get the equation of the tangent.
I'm having trouble here, arranging the equation.
What am I doing wrong?
y - y1 = m(x -x1)
y + 3 = -36/23 (x - 2)
y + 3 = (-36/23)x + 72/23
Not sure how to arrange that.
The gradient and equation of the normal will be easier if I knew how to arrange this.
Thanks.