Spaceman Spiff
New member
the answer is
y = C1e^(3t) + C2e^(-t)
How is it done?
y = C1e^(3t) + C2e^(-t)
How is it done?
Find a general solution to the ODE y'' - 2y' - 3y = 0 . Assume that all Cs are arbitrary constants?
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