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What is the change in entropy of mercury vapor (Lv = 2.7 105 J/kg) when 0.35 kg of it condenses to a liquid at its boiling point of 357°C?
This is what I did and i still cant get the right answer.
Q=M*Lv
Q=.35Kg*2.7 x10^5
=94500.0
delt S=Q/T
=94500/630.00
=149.96 but this answer is not right .I'm what i'm doing wrong
Thank you for the help
This is what I did and i still cant get the right answer.
Q=M*Lv
Q=.35Kg*2.7 x10^5
=94500.0
delt S=Q/T
=94500/630.00
=149.96 but this answer is not right .I'm what i'm doing wrong
Thank you for the help