C chrissy New member Oct 1, 2009 #1 Determine the enthalpy for this reaction: Ca(OH)_2 +CO_2 =CaCO_3 + H_2O CO_2 = -393 kJ/mol Ca(OH)_2 = -987 kJ/mol CaCO_3= -1207 kJ/mol H_2O= -286 kJ/mol answer in kJ/mol
Determine the enthalpy for this reaction: Ca(OH)_2 +CO_2 =CaCO_3 + H_2O CO_2 = -393 kJ/mol Ca(OH)_2 = -987 kJ/mol CaCO_3= -1207 kJ/mol H_2O= -286 kJ/mol answer in kJ/mol