Given integral: 1/(y^4 + 1) dydx bound: (cube root of x) <= y <= 2 0<= x <= 8
I sketched and reversed the order from dydx to dxdy. I just want to know if my bounds are correct for the new integral: 0<= y <=8 y^3 <= x <=2
Also, please solve your integral so that I can also check if my evaluated integral is correct (if I got the bounds right).
I sketched and reversed the order from dydx to dxdy. I just want to know if my bounds are correct for the new integral: 0<= y <=8 y^3 <= x <=2
Also, please solve your integral so that I can also check if my evaluated integral is correct (if I got the bounds right).