Circle N has a circumference of 16(pi) milimiters. What is the area of the

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TheQuestionSeeker

New member
shaded region to the nearest tenth? On the left and right of the circle there are two angles of 120 degrees.


Can I get some help?
There are two angles of 120 degrees on the left and right, they are the shaded parts of the circle.
 
well this is how oyu dos its:

first you add the 120's together to get the total shaded angle.
so there is 240 degrees of shaded angle
since there is 360 degrees in a circle and 240 is shaded then 240/360 is the percent of the shaded circle. that is 2/3.

so no the circumference is 16pi since C=2pi*r we solve for r.
16 pi = 2*pi*r
16 = 2r
r=8

now use this radius to find the area of the entire circle
a=pi*r^2
a=pi*8^2
a=64pi

sice we determined that 2/3 of the circle is shaded we take 2/3 of 64pi
2/3 * 64pi

so the area of the shaded region is 42 2/3 pi. or 131.04 sq mm
 
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