Chemistry Stoichiometry Question?

Ivan

New member
Please help me solve this with instructions of how to do so. Im not sure if i am understanding what it is asking. I tried percent composition than multiplying it by the amount of moles than avagadro's number. didnt work.

Calculate number of O atoms in 4.82×10^−3 mol Al(NO3)3.
 
One mole of Al(NO3)3 contains
1 mole of Al
3 moles of N and
3 x 3 = 9 moles of oxigen

moles Oxigen = 9 x 4.82 x 10^-3=4.54 x 10^-2
atoms of oxigen = 4.54 x 10^-2 x 6.02 x 10^23=2.61 x 10^22
 
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