A amit m New member Jan 9, 2010 #1 Fe2O3 + 3H2O -------------> 2Fe(OH)3 (59g Fe2O3 x 1 mol Fe2O3/160 g Fe2O3) x 2 mol 2Fe(OH)3/1 mol Fe2O3 = 0.74 moles
Fe2O3 + 3H2O -------------> 2Fe(OH)3 (59g Fe2O3 x 1 mol Fe2O3/160 g Fe2O3) x 2 mol 2Fe(OH)3/1 mol Fe2O3 = 0.74 moles
J Jessica M New member Jan 9, 2010 #2 When 59 grams of iron(III) oxide reacts with excess water, how many moles of the product will be formed? THis is a synthesis reaction!
When 59 grams of iron(III) oxide reacts with excess water, how many moles of the product will be formed? THis is a synthesis reaction!
A amit m New member Jan 9, 2010 #3 Fe2O3 + 3H2O -------------> 2Fe(OH)3 (59g Fe2O3 x 1 mol Fe2O3/160 g Fe2O3) x 2 mol 2Fe(OH)3/1 mol Fe2O3 = 0.74 moles
Fe2O3 + 3H2O -------------> 2Fe(OH)3 (59g Fe2O3 x 1 mol Fe2O3/160 g Fe2O3) x 2 mol 2Fe(OH)3/1 mol Fe2O3 = 0.74 moles
