S
softballplaya_714
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Assuming that you used 5.00 mL of 0.010 M Cu(NO3)2 and 1.00 mL of 3.0 M NH3 AND that the reaction goes to completion, please complete the following reaction table.
Cu^2+ + 4NH3 --> Cu(NH3)4^2+ (Kf = 4.8 x 10^12)
initial
delta
final
Cu^2+ + 4NH3 --> Cu(NH3)4^2+ (Kf = 4.8 x 10^12)
initial
delta
final