A
A.TAKA
Guest
I just started taking AP Chemistry, and I'm stuck on one of the homework problems. I don't need the exact number answer, just how to figure it out.
Iron pyrite is often called "fools gold." Suppose you have a gold that you believe is fools gold. You lower the sample into the water in a graduated cylinder, and the water level rises from 47.5 mL to 52.2 mL. Is the sample fool's gold (d=5.00 g/cm3) or real gold (d=19.3 g/cm3)?
I'm assuming d is density. I attempted to use d=m/v, and I subtracted 47.5 from 52.2 to get 4.7 mL/cm3, which i believe is the volume. The two densities are given, but I do not know how to find the mass, or how to solve it in the first place.
Any advice? THANK YOU!
Iron pyrite is often called "fools gold." Suppose you have a gold that you believe is fools gold. You lower the sample into the water in a graduated cylinder, and the water level rises from 47.5 mL to 52.2 mL. Is the sample fool's gold (d=5.00 g/cm3) or real gold (d=19.3 g/cm3)?
I'm assuming d is density. I attempted to use d=m/v, and I subtracted 47.5 from 52.2 to get 4.7 mL/cm3, which i believe is the volume. The two densities are given, but I do not know how to find the mass, or how to solve it in the first place.
Any advice? THANK YOU!