Red mercury(II) oxide decomposes at high temperatures to from mercury metal and oxygen gas:
2HgO(s) --> 2Hg(l) + O2(g)
If 3.55 moles of HgO decompose to form 1.54 moles of O2 and 618 g of Hg, what is the percent yield of this reaction?
A. 13.2%
B. 42.5%
C. 56.6%
D. 86.8%
Please have a reason to why or how you solved this question.
Thanks!
2HgO(s) --> 2Hg(l) + O2(g)
If 3.55 moles of HgO decompose to form 1.54 moles of O2 and 618 g of Hg, what is the percent yield of this reaction?
A. 13.2%
B. 42.5%
C. 56.6%
D. 86.8%
Please have a reason to why or how you solved this question.
Thanks!