J John S New member Jun 13, 2009 #1 how can this equation work: CuCO3 + H2SO4 --> CuSO4 + CO2 + H2O --- the reaction is a double displacement, so the Hydrogen displaces the Copper and vice versa so it should be HCO3 + CuSO4 -- why is it not
how can this equation work: CuCO3 + H2SO4 --> CuSO4 + CO2 + H2O --- the reaction is a double displacement, so the Hydrogen displaces the Copper and vice versa so it should be HCO3 + CuSO4 -- why is it not
S so yeah New member Jun 13, 2009 #2 first off you maybe mean H2CO3 + CuSO4 And secondly H2SO4 is a very instable acid and breaks up into H2O and CO2.
first off you maybe mean H2CO3 + CuSO4 And secondly H2SO4 is a very instable acid and breaks up into H2O and CO2.
S so yeah New member Jun 13, 2009 #3 first off you maybe mean H2CO3 + CuSO4 And secondly H2SO4 is a very instable acid and breaks up into H2O and CO2.
first off you maybe mean H2CO3 + CuSO4 And secondly H2SO4 is a very instable acid and breaks up into H2O and CO2.
