Chemistry homework question.?

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NeverGiveUp♥

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Ethylene (C2H4), an important industrial organic chemical, can be prepared by heating hexane (C6H14) at 800 degrees C.

C6H14 ------> C2H4 + other products

If the yield of ethylene production is 42.5%, what mass of hexane must be reacted to produce 481g of ethylene?

The answer is: 3.47 * 10^3g

If you understand how to do this, could you please explain it to me? I have been trying different ways for about an hour and I can't seem to understand it. Would you use the percent yield equation to go about this problem?

Thank you SO much in advance x x x x
 
The ratio of C6H14 to C2H4 is 1 : 1

That means 1 mol of C6H14 will produce 1 mol of C2H4 if the % yield is 100%.

Now, you need to produce 481g of ethylene.
481 g of ethylene = 481 / 28 = 17.179 mol

Since the efficiency is only 42.5%, the number of moles of hexane must be 17.179 x 100 / 42.5 = 40.42 mol

Hence, the mass of hexane needed = 42.42 x 86

....................................................= 3.47 x 10^3 g
 
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